Honors Physics Syllabus 2018 – 2019
Teacher: Mr. Glenton McBeth
Email: [email protected]
Room: 817
Phone: (951) 729-9296 ext.
Tuesday Make – Ups/Tutoring Thursday: 7:00 – 7:30 am
Course Description
Welcome to Honors Physics! This course seeks to broaden students' horizon on a wide range of physics topics. It prepares students for introductory college physics course which provides a launching pad for careers such as Engineering, Data analysis, IT consultant and the Medical field.To succeed optimally in this course, students need to have a strong background in precalculus because physics relies heavily on theories and experimentations that are highly quantitative to support conclusions. Accordingly, a foundational knowledge of algebra is required to succeed in this course. For example, students will be required to find the slope and area under graphs. In addition to that, students should have a good handle on basic trigonometrical functions. In this course students will learn about Mechanics, States of matter, Waves and light, Electricity and magnetism and Modern physics. Moreover, students will be required to apply content knowledge to laboratory procedures, laboratory safety measures, scientific thinking and reasoning, problem solving, and project –based applications. Furthermore, students will be expected to construct and judge the validity of a logical argument, demonstrate effective oral and listening skills, use technology in a responsible manner and model productive citizenship.
Elsinore High School
Physics Practice Test : Work, Energy and Power
Teacher: G. Mcbeth
11/28/2918
Instruction: Do all questions.
Ans. ½ mv2 = ½ x 40 x 9 = 180J
How much work was done to move the box?
Ans. W = F x d = 20N x 5m = 100J
then what is the car’s final velocity?
Ans. F = ma , a = F/m = 250N/500kg = 0.5 m/s2
v2 = u2 + 2ad, v = 2 x 0.5 x 50= 7.07m/s
a height if 5 m. What is the change in the piano’s gravitational potential energy?
Ans. mgh = 250 x 9.8 x 5 = 12250 J
of 5 N on a rope attached to the box at an angle of 600. How much work has he done on the
Box?
Ans. W = 5cos60x 25 = 62.5 J
from rest. What is the box’s velocity at the bottom of the hill?
Ans. mgh = ½ mv2 at the bottom
2.5 x 9.8 x 5 = ½ x 2.5 x v2
122.5 = 1.25 v2
v = 122.5/1.25 = 9.90 m/s
arrow has a mass of 10.0 g. When he releases the string, what is the velocity of the arrow
when it leaves the bow?
Ans. W = ½ mv2
35N x 0.1m = 0.5 x v2
v = 3.5/.5 = 2.6 m/s
the frictional force on the car?
Ans. v2 = u2 + 2ad
0 = 152 + 2 x 5 x a
-225/10 = a
a = -22.5 m/s2
F = ma
F = 500 x -22.5 = - 11250 N
cm horizontally from the equilibrium position, what is the maximum kinetic energy?
Ans. ½ k x2 = ½ mv2
.5 x 1,250 x .062 = kinetic energy
= 2.25 J
Ans. F = kx
F = 150 x 0.25 = 37.5 N
energy stored in the spring?
½ kx2 = .5 x 200 x 0.252 = 6.25 J
m from equilibrium. When the block is let go, what is its velocity as it passes the equilibrium
Point?
Ans. ½ kx2 = ½ mv2
0.5 x 50 x (0.1)2 = 0.5 x 0.5 v2
0.25 = 0.25 v2
v = 1 m/s
Cannon 2 is 3 times as long as the barrel of Cannon 1. How does the velocity of a cannonball
fired from Cannon 2 compared with that of the ball fired from Cannon 1?
the glider’s speed increases to 60.0 m/s. What is the approximate force of the tailwind?
Ans. Work = ½ mv2 - ½ mu2 = F x d
F x 600 = ½ x 350 x 602 - ½ x 350 x 502
F x 600 = 630000 - 437500
F x 600 = 192500
F = 192500/600 = 320.8 N
the kinetic energy increases by 11.5 J. How can you account for the the difference in energy?
Ans. 2J of energy represent heat produced by the box.
object’s velocity by .50 m/s. What was the mass of the object?
Ans. v2 = u2 + 2ad
0.52 = 0 + 2 x 2.5 x a
a = 0.104 m/s2
F = ma
m = F/a
m = 1.0/0.104 = 9.62 kg
18.A 35.0 -kg stuntman free falls from a building for 62 m and hits an airbag. The airbag exerts
a force on him as he depresses it 5.0 m and comes to a complete stop. What is the average
force exerted by the airbag?
mgh = Work done
mgh = F x d
35.0 x 9.8 x 62 = F x 5.0
F = 4253.2 N
30 m in 1 min. What is his power?
Ans. P = W/t
P = 50 x 30 / 60s = 25W
Questions 20 -22 refer to the figure below. For each question, assume that the roller coaster was initially moving to the right as it approaches point A. Also assume air drag and tract friction are negligible.
20.The diagram above depicts a frictionless roller coaster tract with various locations labeled
A through E. At which locations will a roller coaster car have the same gravitational
potential energy?
constant 10 - N force along the axis of the handle and moves the lawn mower a horizontal
distance of 50 m in 2.5 min. What is the man’s power output?
Ans. P = W/t = 10cos30x 50/ 150s = 433.01/150 = 2.89 W
Ans. KE = ½ x 1,000 x 1722 = 14792000J
then what force does the riffle exert on the bullet?
Ans. KE = Work done
½ x 0.002 x 4252 = F x 0.51
180.625 = F x 0.51
F = 354.17N